First, identify the first term $a$ and the common difference $d$ of the arithmetic series from the given terms. Then, use these values to find the number of terms $n$ in the series.

Yes, that's correct. The first term $a$ is 4, and the common difference $d$ is 6. Next, use the formula for the nth term of an arithmetic sequence, $T_n = a + (n-1)d$, to find the number of terms $n$ when $T_n = 1354$.

Set up the equation for the nth term: $1354 = 4 + (n-1) \cdot 6.$ Solve this equation to find the value of $n$.

First, subtract 4 from both sides of the equation: $1354 - 4 = (n-1) \cdot 6.$ Then, simplify the left side and divide both sides by 6 to solve for $n-1$. Finally, add 1 to find $n$.

Correct. Now, solve for $n$ by adding 1 to the result of $1350/6$. This will give you the total number of terms in the series.

Exactly, so $n = 225 + 1$. Now you have the total number of terms $n$ in the series.

Yes, that's correct. Now, use the formula for the sum of an arithmetic series $S_n = \frac{n}{2} (a + l)$ where $n$ is the number of terms, $a$ is the first term, and $l$ is the last term. You can now calculate the sum of the series.

To correct your calculation: you should use the last term of the series, which is 1354, not 6. So, substitute $l = 1354$ and $a = 4$ into the sum formula. Calculate $S_n = \frac{226}{2} (4 + 1354)$ to find the sum of the series.

Yes, that's correct! You've successfully calculated the sum of the arithmetic series. Well done!